The load-carrying capacities of open, ZZ, and 2RS bearings are identical.
The maximum rotational speed is specified for ZZ bearings (lubricated with grease). For 2RS bearings, two-thirds (2/3) of this value should be used.
The maximum operating temperature for bearings is 120°C for ZZ type and 90°C for 2RS type.
C (kN) Max. d/d (ZZ for ZZ grease-lubricated bearings)
6010 21,79 8.000
6011 28,27 7.200
6012 29,35 6.700
6014 38,05 5.700
6210 35,07 6.600
6211 43,38 6.100
6212 52,42 5.400
6214 62,19 4.700
6310 62,00 5.300
6311 72,00 4.800
6312 81,85 4.500
6314 104,00 3.800
The recommended pulley tolerances are between −40 and −10 microns, meaning the pulley diameter should be machined within 89.96 mm to 89.99 mm to ensure a tight fit with the bearing.
The shaft tolerances are between −9 and −20 microns, meaning the shaft diameter should be approximately between 49.99 mm and 49.98 mm to allow a loose fit with the bearing. To prevent the shaft from coming out of the bearing, measures such as using a retaining ring should be taken.
During the installation of the bearings into the pulley, it is important to ensure that the mounting force is applied only to the outer ring of the bearing to avoid damage.
To achieve this, a tubular fixture designed to press against the outer ring of the bearing can be used. This fixture may be made from a clean, burr-free tube with an inner diameter of 83 mm and an outer diameter of 89 mm, ensuring proper contact with the outer race.
Finally, it is important that the assembly environment and the pulley housing are clean and free from dirt, burrs, and metal particles.
If a service life calculation for the bearing is also desired, the following formula can be used.
L=(c/p) ^3 (C divided by P, raised to the power of 3)
C: Load-carrying capacity of the bearing. For a 6210 bearing, it is 35.07 kN.
P: Load applied to the bearing.
L: Number of revolutions the bearing will rotate, expressed in millions of revolutions.
If you want the service life in hours, the following formula will be used:
Lh: 1000000*L/(60*n)
Lh: Service life in hours
n: Average speed of the bearing during operation, in revolutions per minute (RPM)
As an Example:
c:35 kN p:3,56 kN n:400 d/dk (RPM)
35 KN/9,81 :3,56 3560kg (Maximum load that can be applied to the bearing)
L= (35/3,56) ^3=950 million revolutions
Lh=1000000*950/ (60*400) =39583 hours
If the system operates for an average of 5 hours per day:
39,583 / 5 = 7,917 days, which corresponds to approximately 21 years of service life.